1873 Rhode Island gubernatorial election
April 2, 1873
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County results Howard: 60–70% 70–80% >90% | |||||||||||||||||
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| Elections in Rhode Island |
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The 1873 Rhode Island gubernatorial election was held on April 2, 1873, in order to elect the governor of Rhode Island. Republican nominee Henry Howard defeated Democratic nominee Benjamin G. Chace.[1]
General election
On election day, April 2, 1873, Republican nominee Henry Howard won the election by a margin of 5,870 votes against his opponent Democratic nominee Benjamin G. Chace, thereby retaining Republican control over the office of governor. Howard was sworn in as the 32nd governor of Rhode Island on May 6, 1873.[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | Henry Howard | 9,656 | 71.68 | |
| Democratic | Benjamin G. Chace | 3,786 | 28.11 | |
| Scattering | 29 | 0.21 | ||
| Total votes | 13,471 | 100.00 | ||
| Republican hold | ||||
References
- ^ "Henry Howard". National Governors Association. Retrieved 2024-04-08.
- ^ "RI Governor". ourcampaigns.com. October 6, 2005. Retrieved 2024-04-08.