1868 Rhode Island gubernatorial election
April 1, 1868
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County results Burnside: 60–70% 80–90% | |||||||||||||||||
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| Elections in Rhode Island |
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The 1868 Rhode Island gubernatorial election was held on April 1, 1868, in order to elect the governor of Rhode Island. Incumbent Republican governor Ambrose Burnside won re-election against Democratic nominee Lyman Pierce in a rematch of the 1866 and 1867 election.[1]
General election
On election day, April 1, 1868, incumbent Republican governor Ambrose Burnside won re-election by a margin of 6,648 votes against his opponent Democratic nominee Lyman Pierce, thereby retaining Republican control over the office of Governor. Burnside was sworn in for his third term on May 4, 1868.
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | Ambrose Burnside (incumbent) | 10,038 | 63.61 | |
| Democratic | Lyman Pierce | 5,731 | 36.32 | |
| Scattering | 11 | 0.07 | ||
| Total votes | 15,780 | 100.00 | ||
| Republican hold | ||||
References
- ^ "Ambrose Burnside". National Governors Association. Retrieved 2024-04-07.
- ^ United States Gubernatorial Elections 1861-1911 (Michael J. Dubin) Page 478