1796 United States presidential election in Rhode Island|
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The 1796 United States presidential election in Rhode Island took place between November 4 to December 7, 1796, as part of the 1796 United States presidential election. Voters chose four representatives, or electors to the Electoral College who voted for president and vice president.
During this election, Rhode Island cast its four electoral votes for John Adams.[1]
Results
See also
References
- ^ "A New Nation Votes". elections.lib.tufts.edu. Retrieved August 29, 2024.
- ^ "A New Nation Votes". elections.lib.tufts.edu. Retrieved August 29, 2024.
- ^ Dubin, Michael J. (2002). United States Presidential Elections, 1788-1860: The Official Results by County and State. Jefferson, North Carolina: McFarland. p. xii. ISBN 0-7864-1017-5.
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Other 1796 elections | |
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