2025 Cranbrook Tennis Classic – Doubles
| Doubles | |
|---|---|
| 2025 Cranbrook Tennis Classic | |
| Champions | Hsu Yu-hsiou Huang Tsung-hao |
| Runners-up | Theodore Winegar Michael Zheng |
| Score | 4–6, 6–3, [11–9] |
Ryan Seggerman and Patrik Trhac were the defending champions[1] but chose not to defend their title.
Hsu Yu-hsiou and Huang Tsung-hao won the title after defeating Theodore Winegar and Michael Zheng 4–6, 6–3, [11–9] in the final.[2]
Seeds
- Blake Bayldon / Trey Hilderbrand (quarterfinals)
- Anirudh Chandrasekar / Ramkumar Ramanathan (quarterfinals)
- Niki Kaliyanda Poonacha / Jeevan Nedunchezhiyan (quarterfinals)
- Patrick Harper / Joshua Sheehy (quarterfinals)
Draw
Key
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- ITF = ITF entry
- PR = Protected ranking
- SR = Special ranking
- SE = Special exempt
- JE = Junior exempt
- JR = Junior Accelerator Programme entrant
- CO = College Accelerator Programme entrant
- NG = Next Gen Accelerator Program entrant
- w/o = Walkover
- r = Retired
- d = Defaulted
Draw
| First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
| 1 | B Bayldon T Hilderbrand | 6 | 4 | [10] | |||||||||||||||||||||||
| M Imamura Y Shimizu | 4 | 6 | [8] | 1 | B Bayldon T Hilderbrand | 6 | 4 | [3] | |||||||||||||||||||
| Kris van Wyk T-l Wu | 0r | Y-h Hsu T-h Huang | 0 | 6 | [10] | ||||||||||||||||||||||
| Y-h Hsu T-h Huang | 3 | Y-h Hsu T-h Huang | 3 | 6 | [10] | ||||||||||||||||||||||
| 3 | N Kaliyanda Poonacha J Nedunchezhiyan | 64 | 6 | [10] | PR | J Jung R Stalder | 6 | 3 | [8] | ||||||||||||||||||
| J Maginley E Spizzirri | 77 | 4 | [8] | 3 | N Kaliyanda Poonacha J Nedunchezhiyan | 1 | 2 | ||||||||||||||||||||
| PR | J Jung R Stalder | 6 | 7 | PR | J Jung R Stalder | 6 | 6 | ||||||||||||||||||||
| Ryuki Matsuda K Stevenson | 3 | 5 | Y-h Hsu T-h Huang | 4 | 6 | [11] | |||||||||||||||||||||
| WC | T Winegar M Zheng | 77 | 6 | WC | T Winegar M Zheng | 6 | 3 | [9] | |||||||||||||||||||
| M Kiger Patrick Maloney | 64 | 1 | WC | T Winegar M Zheng | 6 | 4 | [10] | ||||||||||||||||||||
| K Pearson L Tu | 6 | 4 | [8] | 4 | P Harper J Sheehy | 3 | 6 | [7] | |||||||||||||||||||
| 4 | P Harper J Sheehy | 2 | 6 | [10] | WC | T Winegar M Zheng | w/o | ||||||||||||||||||||
| WC | S Dostanic B Kittay | 2 | 6 | [10] | WC | S Dostanic B Kittay | |||||||||||||||||||||
| N Mejía C Rodríguez | 6 | 3 | [5] | WC | S Dostanic B Kittay | 4 | 6 | [10] | |||||||||||||||||||
| 2 | A Chandrasekar R Ramanathan | 6 | 4 | [7] | |||||||||||||||||||||||