2025 China International Suzhou – Doubles
| Doubles | |
|---|---|
| 2025 China International Suzhou | |
| Champions | Blake Bayldon Ray Ho |
| Runners-up | S D Prajwal Dev Nitin Kumar Sinha |
| Score | 6–4, 6–3 |
Gao Xin and Sun Fajing were the defending champions from when the tournament was last held in 2017,[1] but they chose not to defend their title.
Blake Bayldon and Ray Ho won the title after defeating S D Prajwal Dev and Nitin Kumar Sinha 6–4, 6–3 in the final.
Seeds
- Blake Bayldon / Ray Ho (champions)
- Finn Reynolds / James Watt (quarterfinals)
- Nathaniel Lammons / Jean-Julien Rojer (semifinals)
- Kaito Uesugi / Seita Watanabe (first round)
Draw
Key
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- ITF = ITF entry
- PR = Protected ranking
- SR = Special ranking
- SE = Special exempt
- JE = Junior exempt
- JR = Junior Accelerator Programme entrant
- CO = College Accelerator Programme entrant
- NG = Next Gen Accelerator Program entrant
- w/o = Walkover
- r = Retired
- d = Defaulted
Draw
| First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
| 1 | B Bayldon R Ho | 77 | 6 | ||||||||||||||||||||||||
| FC Alcantara L Harris | 63 | 4 | 1 | B Bayldon R Ho | 77 | 77 | |||||||||||||||||||||
| P Isaro N Kaliyanda Poonacha | 6 | 6 | P Isaro N Kaliyanda Poonacha | 65 | 62 | ||||||||||||||||||||||
| Y-h Hsu T-h Huang | 2 | 2 | 1 | B Bayldon R Ho | 7 | 6 | |||||||||||||||||||||
| 4 | K Uesugi S Watanabe | 6 | 3 | [6] | Y Shimizu N Tajima | 5 | 3 | ||||||||||||||||||||
| Y Shimizu N Tajima | 4 | 6 | [10] | Y Shimizu N Tajima | 7 | 6 | |||||||||||||||||||||
| E Agafonov I Simakin | 6 | 77 | E Agafonov I Simakin | 5 | 3 | ||||||||||||||||||||||
| WC | J Cui R Te | 1 | 63 | 1 | B Bayldon R Ho | 6 | 6 | ||||||||||||||||||||
| Ryuki Matsuda K Samrej | 6 | 6 | SDP Dev NK Sinha | 4 | 3 | ||||||||||||||||||||||
| WC | J Shang Zhang Zurui | 1 | 3 | R Matsuda K Samrej | 3 | 3 | |||||||||||||||||||||
| F Ferreira Silva H Rocha | 1 | 4 | 3 | N Lammons J-J Rojer | 6 | 6 | |||||||||||||||||||||
| 3 | N Lammons J-J Rojer | 6 | 6 | 3 | N Lammons J-J Rojer | 4 | 6 | [8] | |||||||||||||||||||
| SDP Dev Nitin Kumar Sinha | 4 | 77 | [10] | SDP Dev NK Sinha | 6 | 2 | [10] | ||||||||||||||||||||
| PR | J Jung J Nedunchezhiyan | 6 | 64 | [8] | SDP Dev NK Sinha | 77 | 6 | ||||||||||||||||||||
| K Isomura A Wang | 4 | 61 | 2 | F Reynolds J Watt | 64 | 2 | |||||||||||||||||||||
| 2 | F Reynolds J Watt | 6 | 77 | ||||||||||||||||||||||||
References
- ^ Heer, Florian (October 29, 2017). "Kecmanovic Takes Maiden ATP Challenger Crown In Suzhou".