2020 Open du Pays d'Aix – Singles

Singles
2020 Open du Pays d'Aix
Champion Oscar Otte
Runner-up Thiago Seyboth Wild
Score6–2, 6–7(4–7), 6–4
Main article: 2020 Open du Pays d'Aix

Pablo Cuevas was the defending champion[1] but lost in the quarterfinals to Daniel Altmaier.

Oscar Otte won the title after defeating Thiago Seyboth Wild 6–2, 6–7(4–7), 6–4 in the final.

Seeds

  1. Gilles Simon (first round)
  2. Pablo Cuevas (quarterfinals)
  3. Gianluca Mager (first round)
  4. Hugo Dellien (first round)
  5. Roberto Carballés Baena (second round)
  6. Alexei Popyrin (first round)
  7. Federico Coria (first round)
  8. Marco Cecchinato (second round)

Draw

Key

Finals

Semifinals Final
          
  Alejandro Tabilo 64 3
Thiago Seyboth Wild 77 6
Thiago Seyboth Wild 2 77 4
SE Oscar Otte 6 64 6
SE Oscar Otte 5
SE Daniel Altmaier 4r

Top half

First round Second round Quarterfinals Semifinals
1/WC G Simon 5 2
F Gaio 7 6 F Gaio 6 6
Q E Ymer 6 2 6 Q E Ymer 4 4
LL R Bemelmans 4 6 4 F Gaio 6 2 4
A Tabilo 7 7 A Tabilo 4 6 6
R Marcora 5 5 A Tabilo 6 77
M Safwat 0 1 8 M Cecchinato 3 65
8 M Cecchinato 6 6 A Tabilo 64 3
3 G Mager 3 5 T Seyboth Wild 77 6
T Seyboth Wild 6 7 T Seyboth Wild 6 7
Q H Gaston 3 78 3 Q R Cid Subervi 1 5
Q R Cid Subervi 6 66 6 T Seyboth Wild 3 6 6
B Klahn 0 2 A Hoang 6 2 1
A Hoang 6 6 A Hoang 6 6
WC Q Halys 7 6 WC Q Halys 3 3
6 A Popyrin 5 3

Bottom half

First round Second round Quarterfinals Semifinals
5 R Carballés Baena 6 6
PR D Brown 4 4 5 R Carballés Baena 7 3 5
D Petrović 6 63 6 D Petrović 5 6 7
JP Varillas 1 77 2 D Petrović 3 2
LL A Cazaux 3 6 3 SE O Otte 6 6
SE O Otte 6 3 6 SE O Otte 77 6
L Mayer 6 6 L Mayer 65 3
4 H Dellien 3 2 SE O Otte 5
7 F Coria 1 6 3 SE D Altmaier 4r
SE D Altmaier 6 4 6 SE D Altmaier 7 6
P Sousa 3 6 6 P Sousa 5 3
J Jung 6 2 4 SE D Altmaier 7 6
E Gómez 79 3 4 2 P Cuevas 5 3
WC H Mayot 67 6 6 WC H Mayot 3 4
Q R Olivo 2 3 2 P Cuevas 6 6
2 P Cuevas 6 6

References

  1. ^ "Pablo Cuevas in 2019: Another Season of Clay-Court Excellence". December 1, 2019.
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