1966 Maryland Attorney General election
November 8, 1966
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County results Burch: 50–60% 60–70% 70–80% Doub: 50–60% 60–70% | |||||||||||||||||
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| Elections in Maryland |
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| Government |
The 1966 Maryland attorney general election was held on November 8, 1966, in order to elect the attorney general of Maryland. Democratic nominee Francis B. Burch defeated Republican nominee William O. Doub.[1]
General election
On election day, November 8, 1966, Democratic nominee Francis B. Burch won the election by a margin of 262,368 votes against his opponent Republican nominee William O. Doub, thereby retaining Democratic control over the office of attorney general. Burch was sworn in as the 40th attorney general of Maryland on January 3, 1967.[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Francis B. Burch | 530,647 | 66.42 | |
| Republican | William O. Doub | 268,279 | 33.58 | |
| Total votes | 798,926 | 100.00 | ||
| Democratic hold | ||||
References
- ^ "1966 Attorney General General Election Results - Maryland". uselectionatlas.org. May 2, 2016. Retrieved 2024-10-23.
- ^ "MD Attorney General". ourcampaigns.com. August 17, 2004. Retrieved 2024-10-23.