1956 U.S. National Championships – Women's singles

Women's singles
1956 U.S. National Championships
Champion Shirley Fry[1]
Runner-up Althea Gibson[1]
Score6–3, 6–4
Seeds8

First-seeded Shirley Fry defeated Althea Gibson 6–3, 6–4 in the final to win the women's singles tennis title at the 1956 U.S. National Championships.[2][3]

Seeds

The seeded players are listed below. Shirley Fry is the champion; others show in brackets the round in which they were eliminated.

  1. Shirley Fry (champion)
  2. Althea Gibson (finalist)
  3. Louise Brough (quarterfinals)
  4. Dorothy Knode (quarterfinals)
  5. Margaret duPont (quarterfinals)
  6. Shirley Bloomer (semifinals)
  7. Betty Pratt (semifinals)
  8. Darlene Hard (quarterfinals)

Draw

Key

Final eight

Quarterfinals Semifinals Finals
               
1 Shirley Fry 6 4 6
5 Margaret duPont 2 6 3
1 Shirley Fry 6 6
6 Shirley Bloomer 4 4
6 Shirley Bloomer 6 6
3 Louise Brough 3 3
1 Shirley Fry 6 6
2 Althea Gibson 3 4
4 Dorothy Knode 6 0 2
7 Betty Pratt 4 6 6
8 Betty Pratt 1 8
2 Althea Gibson 6 10
8 Darlene Hard 7 1
2 Althea Gibson 9 6

References

  1. ^ a b Collins, Bud (2010). The Bud Collins History of Tennis (2nd ed.). [New York City]: New Chapter Press. p. 471. ISBN 978-0942257700.
  2. ^ G.P. Hughes, ed. (1957). Dunlop Lawn Tennis Annual 1957. London: Ed. J. Burrow & Co. Ltd. pp. 245–247.
  3. ^ "National Tennis Championships Opens Today". The Free Lance–Star. AP. August 31, 1956. p. 12.
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