1865 Iowa gubernatorial election
October 10, 1865
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County results Stone: 50-60% 60-70% 70-80% 80-90% 90-100% Benton: 50-60% 60-70% 70-80% 80-90% No Data/Votes: | |||||||||||||||||
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| Elections in Iowa |
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The 1865 Iowa gubernatorial election was held on October 10, 1865, in order to elect the governor of Iowa. Incumbent Republican governor William M. Stone was re-elected against Democratic nominee Thomas H. Benton.[1]
General election
On election day, October 10, 1865, incumbent Republican governor William M. Stone won re-election by a margin of 16,371 votes against his opponent Democratic nominee Thomas H. Benton, thereby holding Republican control over the office of governor. Stone was sworn in for his second term on January 16, 1866.[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | William M. Stone | 70,461 | 56.41 | |
| Democratic | Thomas H. Benton | 54,090 | 43.31 | |
| Scattering | 353 | 0.28 | ||
| Total votes | 124,904 | 100.00 | ||
| Republican hold | ||||
References
- ^ "William Milo Stone". National Governors Association. Retrieved 2023-11-28.
- ^ "IA Governor". ourcampaigns.com. July 25, 2005. Retrieved 2023-11-28.
- ^ Iowa General Assembly. Journal of the House of Representatives. 1866 sess., 3, accessed November 28, 2023