1836 New Hampshire gubernatorial election
March 8, 1836
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County results Hill: 50–60% 60–70% 80–90% 90-100% | |||||||||||||||||||||
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| Elections in New Hampshire |
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The 1836 New Hampshire gubernatorial election was held on March 8, 1836, to elect the Governor of New Hampshire. The Democratic former U.S. senator from New Hampshire Isaac Hill defeated the Whig candidate Joseph Healey and the Federalist former Attorney General of New Hampshire George Sullivan.[1]
Hill's re-election was considered nearly inevitable, and his opponents struggled to recruit a candidate to contest the election. In March, the Democratic Rhode Island Republican reported that the defunct Federalist Party had nominated Sullivan, but he had declined to run.[2]
General election
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Isaac Hill | 24,904 | 81.22 | |
| Whig | Joseph Healey | 2,566 | 8.37 | |
| Federalist | George Sullivan | 2,230 | 7.27 | |
| Scattering | 961 | 3.14 | ||
| Total votes | 30,661 | 100.00 | ||
| Democratic hold | ||||
References
- ^ "Isaac Hill". National Governors Association. Retrieved 2024-04-02.
- ^ "The New Hampshire federalists [...]". Rhode Island Republican. March 2, 1836.